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其实跟打家劫舍没啥区别 排序去重之后去考虑当前位置和前两个位置之间的关系即可，具体见代码：

class Solution {
public:
    int deleteAndEarn(vector<int>& nums) {
        int n = nums.size();
        if (n == 1) return nums[0];
        unordered_map<int, int> hash;
        for (int i = 0; i < n; i++) {
            ++hash[nums[i]];
        }
        sort(nums.begin(), nums.end());
        int n1 = (unique(nums.begin(), nums.end()) - nums.begin());
        vector<int> dp(n1 + 1, 0);
        dp[0] = 0; dp[1] = nums[0] * hash[nums[0]];
        
        for (int i = 1; i < n1; i++) {
            if (nums[i] - nums[i - 1] == 1) {
                dp[i + 1] = max(dp[i - 1] + nums[i] * hash[nums[i]], dp[i]);
            }
            else {
                dp[i + 1] = dp[i] + nums[i] * hash[nums[i]];
            }
        }

        return dp[n1];
    }
};