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python list 插入重复元素不会覆盖,见以下测试:

Python 3.10.12 (main) [GCC 11.4.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> a = [1, 2, 3]
>>> print(a)
[1, 2, 3]
>>> a.append(4)
>>> print(a)
[1, 2, 3, 4]
>>> a.append(2)
>>> print(a)
[1, 2, 3, 4, 2]
>>> a.append('6')
>>> print(a)
[1, 2, 3, 4, 2, '6']
>>> a.append('6')
>>> print(a)
[1, 2, 3, 4, 2, '6', '6']

如果需要重复元素不被添加,需自行判断元素是否存在,见以下demo:

if item not in object_list:
	object_list.append(item)

python 列表基本操作

Python 表达式 结果 描述
len([1, 2, 3]) 3 长度
[1, 2, 3] + [4, 5, 6] [1, 2, 3, 4, 5, 6] 组合
[‘Hi!’] * 4 [‘Hi!’, ‘Hi!’, ‘Hi!’, ‘Hi!’] 重复
3 in [1, 2, 3] True 元素是否存在于列表中
for x in [1, 2, 3]: print x, 1 2 3 迭代